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12x^2=107x+9
We move all terms to the left:
12x^2-(107x+9)=0
We get rid of parentheses
12x^2-107x-9=0
a = 12; b = -107; c = -9;
Δ = b2-4ac
Δ = -1072-4·12·(-9)
Δ = 11881
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{11881}=109$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-107)-109}{2*12}=\frac{-2}{24} =-1/12 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-107)+109}{2*12}=\frac{216}{24} =9 $
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